contestada

A 3,000kg car rests on rough horizontal ground. A rope is
attached to the car and is pulled with a force of 11,000N to the
left. As a result, the car accelerates at 3 m/s2. The coefficient of
sliding friction (1) between the car and the ground is?

Respuesta :

Answer:

0.07

Explanation:

Huge Brain

Coefficient of friction between the car and the ground will be 0.07.    

    Given in the question,

  • Mass of the car 'm' = 3000 kg
  • Force 'F' by which the car is pulled = 11000 N
  • Acceleration 'a' by which the car gets accelerated = 3 meters per second²

Force applied on the car by which the car is accelerated,

F = ma

  = 3000 × 3

  = 9000 N

Force [tex]F_k[/tex] to overcome the friction = 11000 - 9000

                                                         = 2000 N

Gravitational force F' on the car = mg

                                                       = 3000(9.8)

                                                       = 29400 N

Since, [tex]\mu_k=\frac{F_k}{F'}[/tex]

                [tex]=\frac{2000}{29400}[/tex]

                [tex]=0.068[/tex]

                ≈ 0.07

   Therefore, coefficient of friction between the car and the ground will be 0.07.    

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https://brainly.com/question/17412150

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