There are 108 pigeons that need pigeon coops. Each coop can hold up to 7 pigeons. How many coops are needed for all 108 pigeons?

Respuesta :

15 coops are needed for 108 pigeons

What is unitary method ?

The unitary method is  a technique for solving a problem but first finding the value of a single unit , and then finding the necessary value by multiplying the single unit value

using  unitary method

Total pigeon = 108

each coop can hold = 7 pigeons

7 pigeons are held by = 1 coop

108 pigeons will be held by = 108 / 7 = 15.43 =15

15 coops are needed for 108 pigeons

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There are 108 pigeons that need pigeon coops, each coop can hold up to 7 pigeons, coops are required for all 108 pigeons.

What are pigeons?

"Pigeons are gentle, plump, small-billed birds with a skin saddle (cere) between the bill and forehead."

What are coops?

"Pigeon houses are also sometimes referred to as "coops" although the word seems to have originally applied to the breeding pens inside the housing."

Total number of pigeons that needed coops [tex]=108[/tex]

Number of pigeons each coop can hold [tex]=7[/tex]

Number of coops required

[tex]=\frac{108}{7} \\=15.42\\=16[/tex]

Hence, we need approximately 16 coops for all 108 pigeons.

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