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Naomi works in a music shop and earns $42 per day. She earns an extra $2 for each CD she sells. If Naomi wants to earn at least $80 per day, which inequality shows the minimum number of CDs, n, that she should sell?

42 + 2n ≤ 80, so n ≤ 19
42 + 2n ≥ 80, so n ≥ 19
42 + 2n ≥ 80, so n ≥ 36
42 + 2n ≤ 80, so n ≤ 36

Respuesta :

Answer:

B. 42 + 2n ≥ 80, so n ≥ 19

Step-by-step explanation:

42 + 2n ≥ 80

Subtract 42 from both sides

2n ≥ 38

Divide both sides by 2

n ≥ 19

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Answer:

42 + 2n ≥ 80, so n ≥ 19

Step-by-step explanation:

If she wants to make at least $80 the she would need to sell a number of cedis in addition to her $42

That is:

Let n be the number of CDs

42 + 2n

and to get at least $80, (at least meaning $80 dollars or more)

So that will be:

42 + 2n ≥ 80

So to get at least 80 dollars, she'll have to sell 19 CDs

Why 19 CDs? 42 + 2n which is 42 + 2(19) = 80

Which is why 42 + 2n ≥ 80, so n ≥ 19