A velocity selector uses a fixed electric field of magnitude E and the magnetic field is varied to select particles of various energies. If the electric field strength is 2.2 x 104 N/C, what should be the value of the magnetic field (in tesla) to select protons of velocity 6.4 x 105 m/s

Respuesta :

Answer:

The value is  [tex]B =   0.034 \  T [/tex]

Explanation:

From the question we are told that

  The electric field strength is  [tex]E =  2.2*10^{4} \  N/C[/tex]

   The velocity is  [tex]v  = 6.4 *10^{5} \  m/s[/tex]

Generally the magnetic field is mathematically represented as

      [tex]B =  \frac{E}{v}[/tex]

=>    [tex]B =  \frac{2.2*10^{4}}{6.4 *10^{5}}[/tex]

=>    [tex]B =   0.034 \  T [/tex]