The density (g/cm3) of 48.0 g of a metal if the level of water in a graduated cylinder rises from 25.0 mL to 33.0 mL after the metal is added density will be 6.0 g/cm3. option B is correct.
The density of any substance is the division of the mass of the given substance to the volume of the given substance and its unit is centimeter cube.
where,
density = mass of substance / volume of the substance
mass of substance = 48.0 g
volume of substance = 33.0 - 25.0 = 8 ml
substituting the value in the formula,
density = 48.0 / 8 = 6 cm³
Therefore, density (g/cm3) of 48.0 g of a metal if the level of water in a graduated cylinder rises from 25.0 mL to 33.0 mL after the metal is added density will be 6.0 g/cm3. option B is correct.
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