Use n = 6 and p = 0.25 to complete parts (a) through (d) below.

(a) Construct a binomial probability distribution with the given parameters.

х

P(x)

0

1

2

3

4

5

6

(Round to four decimal places as needed.)

(hl somnute the mean and standard deviation of the random variable using Hy = x.P(x)] and oy =

Respuesta :

Answer:

The binomial probability distribution is shown below.

Step-by-step explanation:

The probability mass function of X is:

[tex]P(X=x)={n\choose x}p^{x}(1-p)^{n-x};x=0,1,2,3..[/tex]

It is provided that n = 6 and p = 0.25.

Construct a binomial probability distribution with the given parameters as follows:

X                                       P (X = x)

0        [tex]P(X=0)={6\choose 0}(0.25)^{0}(1-0.25)^{6-0}= 0.1780[/tex]

1         [tex]P(X=1)={6\choose 1}(0.25)^{1}(1-0.25)^{6-1}= 0.3560[/tex]

2        [tex]P(X=2)={6\choose 2}(0.25)^{2}(1-0.25)^{6-2}= 0.2966[/tex]

3        [tex]P(X=3)={6\choose 3}(0.25)^{3}(1-0.25)^{6-3}= 0.1318[/tex]

4       [tex]P(X=4)={6\choose 4}(0.25)^{4}(1-0.25)^{6-4}= 0.0330[/tex]

5       [tex]P(X=5)={6\choose 5}(0.25)^{5}(1-0.25)^{6-5}= 0.0044[/tex]

6       [tex]P(X=6)={6\choose 6}(0.25)^{6}(1-0.25)^{6-6}= 0.0002[/tex]

Compute the mean and standard deviation as follows:

[tex]\mu=np=6\times0.25=1.50\\\\\sigma=\sqrt{np(1-p)}=\sqrt{6\times 0.25\times (1-0.25)}=1.0607[/tex]

Binomial probability distribution was constructed, and the mean and standard deviation comes to be 1.5 and 1.061 respectively.

As we know that binomial probability distribution is given by

[tex]P(x) = ^nC_xp^x(1-p)^{n-x}[/tex]

What is binomial distribution?

The binomial distribution is a probability distribution that depicts the likelihood that a value will take one of two independent values under a given set of parameters.

Given n=6 & p=0.25

[tex]P(0) = ^6C_0(0.25)^0(1-0.25)^{6-0}[/tex] = 0.1780

[tex]P(1) = ^6C_1(0.25)^1(1-0.25)^{6-1}[/tex]=0.3560

[tex]P(2) = ^6C_2(0.25)^2(1-0.25)^{6-2}[/tex] = 0.2966

[tex]P(0) = ^6C_3(0.25)^3(1-0.25)^{6-3}[/tex] =0.1318

[tex]P(0) = ^6C_4(0.25)^4(1-0.25)^{6-4}[/tex]=0.0330

[tex]P(5) = ^6C_5(0.25)^5(1-0.25)^{6-5}[/tex]=0.0044

[tex]P(6) = ^6C_6(0.25)^6(1-0.25)^{6-6}[/tex]= 0.0002

Mean = np

Mean = 6*0.25

Mean = 1.5

Standard deviation σ = [tex]\sqrt{np(1-p)}[/tex]

σ = [tex]\sqrt{6*0.25(1-0.25)}[/tex]

σ = 1.061

Hence, binomial probability distribution was constructed, and the mean and standard deviation comes to be 1.5 and 1.061 respectively.

To get more about binomial distribution visit:

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