Answer:
[tex]4x + 0.9 \geq 0.1[/tex] is equivalent to the inequality [tex]40x+9 \geq 1[/tex]
Step-by-step explanation:
Given inequality : [tex]4x + 0.9 \geq 0.1[/tex]
We are supposed to find Which of the following is equivalent to the inequality
[tex]4x + 0.9 \geq 0.1[/tex]
[tex]\Rightarrow 4x+\frac{9}{10} \geq \frac{1}{10}[/tex]
Multiply both sides by 10
[tex]\Rightarrow 4(10)x+\frac{9}{10}(10) \geq \frac{1}{10}(10)[/tex]
[tex]\Rightarrow 40x+9 \geq 1[/tex]
[tex]4x + 0.9 \geq 0.1[/tex] is equivalent to the inequality [tex]40x+9 \geq 1[/tex]
So, Option B is true
B) [tex]40x+9 \geq 1[/tex]
