A junk drawer at home contains five pens, two of which work . What is the probability that you randomly grab two pens from the drawer and don’t end up with a pen that works? Express your answer as a fraction in lowest terms or a decimal rounded to the nearest millionth.

Respuesta :

Answer:

The probability is [tex]P(k) = \frac{4}{25}[/tex]

Step-by-step explanation:

From the question we are told that

   The number of pens from the drawer is  n =  5

   The number of pens that doesn't work is  k =  2

The probability that a does not work is

             [tex]p = \frac{k}{n}[/tex]

=>          [tex]p = \frac{2}{5}[/tex]

The probability that a pen works is

           [tex]q = 1- p[/tex]

           [tex]q = 1- \frac{2}{5}[/tex]

    =>   [tex]q = \frac{3}{5}[/tex]

Generally the probability that ending up with a pen that doesn't work is mathematically represented as  

            [tex]P(k) = p^2[/tex]

=>         [tex]P(k) = [\frac{2}{5} ]^2[/tex]

=>        [tex]P(k) = \frac{4}{25}[/tex]

 

The probability that you randomly grab two pens from the drawer and don’t end up with a pen that works is [tex]\dfrac{4}{25}[/tex].

Given information:

The number of pens in the drawer is [tex]n=5[/tex].

The number of pens that doesn't work is [tex]a=2[/tex].

So, the number of pens which works will be, [tex]b=5-2=3[/tex].

The probability of grabbing a pen that doesn't work will be,

[tex]P_a=\dfrac{2}{5}[/tex]

Now, two pens are grabbed randomly from the drawer. So, the probability that you randomly grab two pens from the drawer and don’t end up with a pen that works will be calculated as,

[tex]P=(P_a)^2\\P=\dfrac{2}{5}\times \dfrac{2}{5}\\P=\dfrac{4}{5}[/tex]

Therefore, the value of the required probability will be [tex]\dfrac{4}{5}[/tex].

To know more about the random picking, refer to the link:

https://brainly.com/question/13448455