contestada

The equilibrium constant for the chemical equation N2(g)+3H2(g)↽−−⇀2NH3(g) is Kp=0.0133 at 181 ∘C. Calculate the value of Kc for the reaction at 181 ∘C.

Respuesta :

Answer:

Kc is 18.478

Explanation:

Here we want to calculate Kc given Kp

The equation that links both is given as follows;

Kc = Kp/(RT)^Δn

where Kp = 0.0133

R is molar gas constant = 0.0821 L.atm/mol.k

T is temperature in kelvin = 181 + 273 = 454K

Δn is the change in number of moles between products and reactants = 2-4 = -2

Substituting these values, we have;

Kc = 0.0133/(0.0821 * 454)^-2

Kc = 18.478

Otras preguntas