The average rate of change of the function in the interval is of:
[tex]A = -\frac{1}{14(14 + h)}[/tex]
The average rate of change of a function f(x) over an interval [a,b] is given by:
[tex]A = \frac{f(b) - f(a)}{b - a}[/tex]
In this problem:
Then:
[tex]f(b) - f(a) = \frac{1}{14 + h} - \frac{1}{14} = \frac{14 - 14 - h}{14(14 + h)} = -\frac{h}{14(14 + h)}[/tex]
[tex]A = \frac{-\frac{h}{14(14 + h)}}{3 + h - 3} = -\frac{-\frac{h}{14(14 + h)}}{h} = -\frac{1}{14(14 + h)}[/tex]
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