Step-by-step explanation:
Hey there!
Given;
[tex] {2}^{4x - 1} =32 [/tex]
[tex] {2}^{4x} . {2}^{ - 1} = {2}^{5} [/tex]
[tex] {2}^{4x} . \frac{1}{2} = {2}^{5} [/tex]
[tex] {2}^{4x} = {2}^{5} . {2}^{1} [/tex]
[tex] {2}^{4x} = {2}^{6} [/tex]
[tex]4x = 6[/tex]
[tex]x = \frac{6}{4} [/tex]
[tex]x = \frac{3}{2} [/tex]
7.)
[tex] \sqrt{x} - 3 = 7[/tex]
[tex] \sqrt{x} = 7 + 3[/tex]
[tex]( { \sqrt{x}) }^{2} = {(10)}^{2} [/tex]
X= 100
8.)
[tex]( {x + 1)}^{2} = 81[/tex]
[tex](x + 1) = \sqrt{81} [/tex]
[tex]x + 1 = \sqrt{ {9}^{2} } [/tex]
[tex]x + 1 = 9[/tex]
[tex]x = 9 - 1[/tex]
X=8
Hope it helps...
