Answer:
for A=[tex]\frac{7b-7}{6}[/tex] and for B=[tex]\frac{6a+7}{7}[/tex]
Step-by-step explanation:
For A
[tex]\left(6a-3\right)=\left(7b-10\right)[/tex]
[tex]6a-3+3=7b-10+3[/tex]
[tex]6a=7b-7[/tex]
[tex]\frac{6a}{6}=\frac{7b}{6}-\frac{7}{6}[/tex]
[tex]a=\frac{7b-7}{6}[/tex]
For B
[tex]\left(6a-3\right)=\left(7b-10\right)[/tex]
[tex]7b-10=\left(6a-3\right)[/tex]
[tex]7b-10=6a-3[/tex]
[tex]7b-10+10=6a-3+10[/tex]
[tex]7b=6a+7[/tex]
[tex]\frac{7b}{7}=\frac{6a}{7}+\frac{7}{7}[/tex]
[tex]b=\frac{6a+7}{7}[/tex]
