The box is falling due the attraction of gravitational force (its weight) and it lands at approximately 782.1 meters further from where it was dropped
The reason why the above value of the location is correct is given as follows:
The known parameter of the box are;
Horizontal velocity of the box, vₓ = 100 m/s
The altitude of the plane, h = 300 m
Required:
The location where the box lands
Solution:
The time it takes the box to land is [tex]t =\sqrt{\dfrac{2 \cdot h}{g} }[/tex]
Where;
g = The acceleration due to gravity ≈ 9.81 m/s²
Therefore;
[tex]t =\sqrt{\dfrac{2 \times 300}{9.81} } \approx 7.821[/tex]
The time it takes the box to reach the ground, t ≈ 7.82 seconds
Horizontal distance covered by the by the box during free fall, d, = The distance the box lands relative to where it was dropped from and is given as follows;
d = vₓ × t
∴ d ≈ 100 m/s × 7.821 s = 782.1 m
Therefore;
The distance the box lands relative to where it was dropped from d ≈ 782.1 m
Learn more about free fall motion here:
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