Respuesta :
Answer:
\franc{\left(2ab^{^3}\right)^{^{-1}}}{20\cdot \left(2^{^{-1}}\cdot \:\:ba^5\right)^{^2}}\cdot \left(\frac{4ab^{^{-1}}}{5b}\right)^{^{-2}}
Step-by-step explanation:
Answer:
\franc{\left(2ab^{^3}\right)^{^{-1}}}{20\cdot \left(2^{^{-1}}\cdot \:\:ba^5\right)^{^2}}\cdot \left(\frac{4ab^{^{-1}}}{5b}\right)^{^{-2}}
Step-by-step explanation: