The correct answer to the question is : B) 1.94 Km.
EXPLANATION:
As per the question, the car travels 30.25 Km due west.
The car drives 7.50 km up a hill.
The angle of inclination of the hill with the ground is [tex]\theta=\ 15^{0}[/tex].
We are asked to calculate the vertical displacement of the car.
Resolving 7.50 Km into horizontal and vertical components, we get-
(a) [tex]7.50cos\theta[/tex] which is the horizontal component.
(b) [tex]7.50 sin\theta[/tex] which is the vertical component.
The vertical displacement [ y ] is calculated as -
y = [tex]7.50sin\theta[/tex]
= 7.50sin15
= 1.9411.. m.
= 1.94 m.
Hence, the vertical displacement is 1.94 m.
