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rectangle ABCD and WXYZ have the same length. The width of rectange ABCD is 9 ft, and its area is 162 ft2. The width of rectangle WXYZ is 6 ft. What is the area of rectangle WXYZ?

Respuesta :

DeepakMunesh
for ABCD
9*L = 162 ft2
L = 18
for WXYZ
18*6=108 ft2
18108 ft2

Answer:

[tex]108 ft^{2} \\[/tex]

Step-by-step explanation:

Given,

The length of rectangle ABCD and WXYZ is equal.

Given,

Width of rectangle ABCD [tex]= 9 feet \\[/tex]

Area of the rectangle ABCD= [tex]162 ft^{2}[/tex]

Length of rectangle ABCD [tex]= \frac{Area}{width} \\= \frac{162}{9} \\= 18 feet\\[/tex]

Since,  length of rectangle ABCD and WXYZ is equal

Area of rectangle WXYZ

[tex](Length of ABCD) * 6ft \\= 18 ft * 6 ft \\= 108 ft^{2} \\[/tex]

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