[tex]44g \ \ CO_{2} \ \ \ \rightarrow \ \ \ 12g \ C\\
19,2g \ CO_{2} \ \ \rightarrow \ \ \ x\\\\
x=\frac{19,5g*12g}{44g}\approx5,32g \ \ \ \ \Rightarrow n=\frac{5,32g}{12\frac{g}{mol}}\approx0,44mol\\\\\\
18g \ H_{2}O \ \ \ \rightarrow \ \ \ 2g \ H\\
5,89g \ \ \ \ \ \ \ \rightarrow \ \ \ y\\\\
y=\frac{5,89g*2g}{18g}=0,65g \ \ \ \ \Rightarrow \ n=\frac{0,65g}{1\frac{g}{mol}}=0,65mol\\\\
n_{C}:n_{H}=0,44:0,65\approx1:1\\\\
CH \ - \ empirical \ formula[/tex]