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how to differentiate [tex]f(x)= \frac{5}{x} +1[/tex]

find f'(x) and f'(2) and f'(4)
I know that to differentiate you do
[tex] \lim_{changex \to 0} \frac{f(x+changex)-f(x)}{changex} [/tex] where changex=Δx
but I'm stuck
ples help

Respuesta :

[tex]f(x) = \dfrac{5}{x} =5x^-^1[/tex] 

[tex]f'(x)= -5x^-^2= \dfrac{-5}{x^2} [/tex] 

[tex]\text{plug in x = 2 and x=4}[/tex] 

[tex]f'(2)= \dfrac{-5}{2^2} = 2^2 = 4 = \dfrac{-5}{4} [/tex] 

[tex]f'(4)= \dfrac{-5}{4^2} = 4^2 = 4*4 = 16 = \dfrac{-5}{16} [/tex] 

[tex]\text{Hence solved }[/tex]

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