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A cube of a gold-colored metal with a volume of 59 cm3 has a mass of 980 g. The density of pure gold is 19.3 g/cm 3. Is the metal pure gold? Show calculations to justify your answer

Respuesta :

Yipes
[tex]V=59cm^{3}\\ m=980g\\\\ d=\frac{m}{V}=\frac{980g}{59cm^{3}}\approx16,61\frac{g}{cm^{3}}[/tex]

It's not gold.
Oseni

A gold-colored metal with a volume of 59 cm3 and a mass of 980 g will have a density of 16.61 g/cm3 instead of 19.3 g/cm3

Recall that the density of a substance is the ratio of its mass and that of its volume.

In other words; density = mass/volume

In this case, the mass of the gold-colored metal is 980 g while the volume is 59 cm3

  density of the metal = 980/59

                              = 16.61 g/cm3

Thus, the density of the gold-colored metal is 16.61 g/cm3, instead of 19.3 g/cm3

More on density can be found here: https://brainly.com/question/15164682

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