Answer:
74.07% is the percent by mass of carbon in [tex]C_{10}H_{14}N_2[/tex] .
Explanation:
Molar mass of compound[tex]C_{10}H_{14}N_2[/tex] = M
[tex]M=10\times 12 g/mol+14\times 1g/mol+2\times 14 g/mol= 162g/mol[/tex]
Number of carbon atom = 10
Atomic mass of carbon = 12 g/mol
Percentage of element in compound :
[tex]=\frac{\text{Number of atoms}\times \text{Atomic mass}}{\text{molar mas of compound}}\times 100[/tex]
Mass percentage of Carbon :
[tex]=\frac{10\times 12g/mol}{162 g/mol}\times 100=74.07\%[/tex]
74.07% is the percent by mass of carbon in [tex]C_{10}H_{14}N_2[/tex] .
