a mixture is made by combining 1.64 lb of salt and 4.66 lb of water. what is the percentage of salt (by mass) in this mixture?

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Alleei Alleei · Answer 1 · 2019-09-09T13:56:41+02:00

Answer : The percentage of salt in the mixture is 73.65 %

Explanation : Given,

Mass of salt = 1.64 lb

Mass of water = 4.66 lb

First we have to calculate the mass of mixture.

Mass of mixture = Mass of salt + Mass of water

Mass of mixture = 1.64 + 4.66 = 6.3 lb

Now we have to calculate the percentage of salt in the mixture.

Formula used :

[tex]\% \text{ of salt}=\frac{\text{Mass of salt}}{\text{Mass of mixture}}\times 100[/tex]

Now put all the given vales in this formula, we get:

[tex]\% \text{ of salt}=\frac{4.64lb}{6.3lb}\times 100=73.65\%[/tex]

Therefore, the percentage of salt in the mixture is 73.65 %

Eduard22sly Eduard22sly · Answer 2 · 2021-08-19T16:07:02+02:00

We shall begin the calculation to the question given above by obtaining the mass of the mixture. This can be obtained as follow:

Mass of salt = 1.64 lb

Mass of water = 4.66 lb

Mass of mixture = mass of salt + mass of water

Mass of mixture = 1.64 + 4.66

Finally, we shall determine the percentage of the salt in the mixture. This can be obtained as illustrated below:

Mass of salt = 1.64 lb

Mass of mixture = 6.3 lb

Percentage of salt = [tex]\frac{mass of salt }{mass of mixture} * 100[/tex]

Percentage of salt = [tex]\frac{1.64}{6.3} * 100[/tex]

Therefore, the percentage of the salt in the mixture is 26%

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