In the year 2019, the population of a city is 20,612 people. The population increases at a rate of 1.8% per year. Based
on this rate, during what year would the population of the city exceed 25,000 people?
2027
2029
2031
2032

Respuesta :

Answer:

I believe it is 2031

Step-by-step explanation:

Answer:

B: 2029

Step-by-step explanation:

Interest Formula

[tex]A=P(1+r)^n[/tex]

A= amount

P= initial amount

r= rate/percentage

n= years

All we have to do is plug in the numbers from the word problem to get:

[tex]20,612(0.018+1)^{n} =25,000[/tex]

From here we solve for n:

[tex](1.018)^n=\frac{25,000}{20,612} \\(1.018)^n=1.213\\[/tex]

Get the natural log (ln) of both sides:

[tex]n=\frac{ln(1.213)}{ln(1.018)}[/tex]

n is approximately 10.823

n is the number of years it will take for the population to reach 25,000 people.

2019+10

=2029