Ben
contestada

If [tex]f(x)=x^2-2[/tex] and [tex]g(x)=3x[/tex], what is [tex](f\circ g)(2)[/tex]?

Respuesta :

Answer:

[tex]\boxed{f(6) = 34}[/tex]

Step-by-step explanation:

Composition of functions occurs when we have two functions normally written similar or exactly like f(x) & g(x) - you can have any coefficients to the (x), but the most commonly seen are f(x) and g(x). They are written as either f(g(x)) or (f o g)(x). Because our composition is written as [tex](f \circ g)(2)[/tex], we are replacing the x values in the g(x) function with 2 and simplifying the expression.

[tex]g(2) = 3(2)[/tex]

[tex]g(2) = 6[/tex]

Now, because we are composing the functions, this value we have solved for now replaces the x-values in the f(x) function. So, f(x) becomes f(6), and we use the same manner as above to simplify.

[tex]f(6) = (6)^2-2[/tex]

[tex]f(6) = 36-2[/tex]

[tex]f(6) = 34[/tex]

Therefore, when we compose the functions, our final answer is [tex]\bold{f(6) = 34}[/tex].

LukeG1

Answer:

[tex]\large\boxed{34}[/tex]

Step-by-step explanation:

[tex]f(x) = x^2 - 2[/tex]

[tex]g(x) = 3x[/tex]

[tex](fog)(2)[/tex]

Find g(2)

[tex]g(x) = g(2)[/tex]

[tex]x=2[/tex]

[tex]3x = 3(2) = 6[/tex]

[tex]g(2) = 6[/tex]

Find f(6)

[tex]f(x) = x^2-2[/tex]

Substitute

[tex]f(6) = x^2 - 2[/tex]

[tex]x^2 - 2 = 6^2 - 2[/tex]

[tex]36 - 2 = 34[/tex]

[tex]\large\boxed{34}[/tex]

Hope this helps :)