Answer:
Option [tex]C. \:\:0.07 \:M[/tex] is the right choice.
Explanation:
Write down the equation and balance it.
[tex]3NaOH+H_3PO_4\Rightarrow \:Na_3PO_4+3H_2O[/tex]
For one mole of phosphoric acid, we need three moles of sodium hydroxide.
Concentration of [tex]NaOH[/tex] [tex]=Molarity=\frac{moles}{Volume}[/tex]
Mole of [tex]NaOH[/tex] [tex]= 0.2\times 50\times 10^{-3}[/tex]
[tex]=0.01\:moles[/tex]
Moles of [tex]H_3PO_4=\frac{0.01}{3}=0.0033\:moles[/tex]
Finally:
Concentration of [tex]H_3PO_4=\frac{0.0033}{0.05}=0.067\:M[/tex]