Question -:
Find the third angle of a triangle with 126° and 41° as two of it's angles.
Explanation -:
[tex] \star \: \small{ \rm{ In \: this \: question \: we \: are \: provided \: with }}\\ \small{\rm{ the \: two \: angles \: of \: the \: triangle}} \\ \small{\rm \: {and \: asked \: to \: calculate \: the \: third \: angle.}}[/tex]
Let us assume the third angle as x
We know,
Sum of all angles of the triangle = 180°
According To Question
[tex] \small\bf \blue{ 126° + 41° + x° = 180°}[/tex]
→ 167° + x° = 180°
→ x = 180° - 167° = 13°
[tex] \small\boxed{ \pink{ \frak{ x = 13°}}}[/tex]
Hence, the third angle is 13°.
