First, we have rounded numbers A and B, and we know that:
A + B = 11000
A - B = 3000
Now we can solve this system of equations by isolating one variable in one of the equations, i will choose A in the second equation:
A = 3000 + B.
Now we can replace this into the other equation:
3000 + B + B = 11000
2*B = 11000 - 3000 = 8000
B = 8000/2 = 4000
and:
A - 4000 = 3000
A = 3000 + 4000 = 7000.
But remember that our original numbers are not exactly whole numbers, they are rounded up, so we could write them as:
A = 6999.8 (that would be rounded up to 7000)
B = 3999.7 (that would be rounded up to 4000)
The sum is:
A + B = 10999.5 (notice that this would be rounded up to 11000)
A - B = 3000.1 (this would be rounded down to 3000)
If you want to learn more, you can read:
https://brainly.com/question/116605
An approximated value is used as an estimate of an actual value. Possible numbers that fit the given description are 6999.9 and 4000.2
Let the numbers be x and y. Such that:
[tex]x + y = 11000[/tex]
[tex]x - y = 3000[/tex]
Make x the subject
[tex]x = 3000 + y[/tex]
Substitute [tex]x = 3000 + y[/tex] in [tex]x + y = 11000[/tex]
[tex]3000 + y + y = 11000[/tex]
[tex]3000 + 2y = 11000[/tex]
Collect like terms
[tex]2y = 11000 - 3000[/tex]
[tex]2y = 8000[/tex]
Divide by 2
[tex]y = 4000[/tex]
Recall that:
[tex]x = 3000 + y[/tex]
[tex]x=3000+4000[/tex]
[tex]x = 7000[/tex]
From the question, we understand that the numbers are not whole. i.e. the numbers are approximated.
So, we look for a number that can be approximated to 7000 and 4000.
Possible numbers are:
[tex]x = 6999.9[/tex]
[tex]y = 4000.2[/tex]
Please note that there are several other numbers that fit into the above description.
Using 6999.9 and 4000.2, the sum and difference are:
[tex]x + y =6999.9 + 4000.2[/tex]
[tex]x + y =11000.1[/tex]
[tex]x - y = 6999.9 - 4000.2[/tex]
[tex]x - y = 2999.7[/tex]
Read more about approximated values at:
https://brainly.com/question/19468438
