Answer:
[tex]94.25[/tex]
Explanation:
Given: Handle of jackscrew is 30 cm long. Also, the car raised 2.0 cm with every full turn of the handle.
To find: ideal mechanical advantage of the jack
Solution:
Let [tex]d_e[/tex] denotes the distance over which the effort is applied and [tex]d_r[/tex] denotes the distance that the load travels.
Here,
[tex]d_r=2\,\,cm[/tex]
[tex]d_e=2\pi(length\,\,of\,\,the\,\,handle)=2\pi(30)=60\pi[/tex]
So,
Ideal mechanical advantage of the jack[tex]\frac{d_e}{d_r}=\frac{60\pi}{2}=30\pi=30(\frac{22}{7})=94.25[/tex]
