Answer:
The pressure altitude is [tex]A = 10\ km[/tex]
The density altitude is [tex]\rho = 0.429 kg/m^3[/tex]
Explanation:
From the question we are told that
The outside pressure is [tex]P_o = 2.65*10^{4} N/m^2[/tex]
The outside temperature is [tex]T_o = 215 \ K[/tex]
Generally the density altitude is mathematically represented as
[tex]\rho = \frac{P_o }{RT}[/tex]
Here R is the gas constant with value [tex]R = 287\ J/kg/K[/tex]
So
[tex]\rho = \frac{2.65 (*10^{4}}{287 * 215}[/tex]
=> [tex]\rho = 0.429 kg/m^3[/tex]
Generally the altitude at which the pressure in the question is experience is
[tex]A = 10\ km[/tex]
Thus the pressure altitude is [tex]A = 10\ km[/tex]
