Given :
Diameter of pizza , [tex]D=10\dfrac{1}{3}=\dfrac{31}{3}[/tex] .
To Find :
Is square box of size equal to diameter big enough to fit pizza inside it .
Solution :
Area of pizza :
[tex]A_p=\pi(\dfrac{D}{2})^2\\\\A_p=\pi\times (\dfrac{31}{3\times 2})^2\\\\A_p=83.86\ inch^2[/tex]
Area of square with side equal to diameter :
[tex]A_s=D^2\\\\A_s=(\dfrac{31}{3})^2\\\\A_s=106.78\ inch^2[/tex]
Since , the area of square is more than area of pizza .
Therefore , pizza can easily be fitted .
Hence , this is the required solution .
