The equation of a line that passes through the point (-8,2) and is parallel to the line 3x-2y=12 is 2y - 3x = 28
The equation of a line in point-slope form is expressed as;
[tex](y-y_1)=m(x-x_1)[/tex]
m is the slope of the line
(x1, y1) is the point on the line = (-8, 2)
Given the line 3x - 2y =12
-2y = -3x + 12
y = 3/2 x - 6
The slope of the line is 3/2
Get the required equation:
[tex]y - 2=3/2(x-(-8))\\2(y-2)=3(x+8)\\2y-4 =3x+24\\2y-3x = 28[/tex]
Hence the equation of a line that passes through the point (-8,2) and is parallel to the line 3x-2y=12 is 2y - 3x = 28
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