A student has a 1g sample of each of the following compounds: NaCl, KBr, and KCL Which of the following lists the samples in order of increasing number of moles in the sample?

Respuesta :

Given :

A student has a 1 g sample of each of the following compounds: NaCl, KBr, and KCl.

To Find :

The samples in order of increasing number of moles in the sample.

Solution :

Molecular mass of NaCl, KBr, and KCl is 58.5 g/mol , 119 g/mol and

74.5 g/mol respectively .

Moles of NaCl , [tex]n_1=\dfrac{1}{58.5}=0.017\ mol[/tex].

Moles of KBr , [tex]n_2=\dfrac{1}{119}=0.008\ mol[/tex].

Moles of KCl , [tex]n_2=\dfrac{1}{74.5}=0.013\ mol[/tex].

The order of moles in increasing order is :

KBr , KCl and NaCl .

Hence , this is the required solution .

The increasing order of the moles in sample has been, KBr < KCl < NaCl.

The moles of sample have been defined as the mass of sample with respect to  molar mass. The moles of sample have been given by:

[tex]\text {Moles}=\dfrac{\text {mass}}{mwt}[/tex]

The molecular mass of the sample has been given by mwt.

The moles in 1 g mass of the following samples has been given by:

  • Moles of NaCl:

[tex]\rm Moles=\dfrac{1}{58.44}\\Moies=0.017\;mol[/tex]

1 gram sample of NaCl has been 0.017  mol.

  • Moles of KBr:

[tex]\rm Moles=\dfrac{1}{119.002} \\Moles=0.008\;mol[/tex]

1 gram sample of KBr has been 0.008 mol.

  • Moles of KCl:

[tex]\rm Moles=\dfrac{1}{74.5513} \\Moles=0.013\;mol[/tex]

1 gram sample of KCl has been 0.0.13 mol.

The increasing order of the moles in sample has been, KBr < KCl < NaCl.

For more information about moles in a sample, refer to the link:

https://brainly.com/question/4816100