Answer:
The pressure in pipe b is 33.4 kpa.
Explanation:
Given that,
Pressure in pipe a = 30 mm hg vacuum
Differential reading = 0.30 m
We need to calculate the pressure in pipe b
Using diagram
[tex]P_{B}+W_{oil}(h_{1}+h_{2})-W_{Hg}(h_{2})-W_{H_{O}}(h_{1})=P_{A}[/tex]
Where, P = pressure
W= specific weight
Put the value into the formula
[tex]P_{B}+W_{oil}(0.15+0.30)-W_{Hg}(0.3)-W_{H_{2}O}(0.15)=-W_{Hg}(0.030)[/tex]
Put the value of specific weight
[tex]P_{B}=-(133)\times(0.030)-(8.95)\times(0.45)+133\times(0.3)+9.80\times0.15[/tex]
[tex]P_{B}=33.4\ kPa[/tex]
Hence, The pressure in pipe b is 33.4 kpa.
