Answer:
Acceleration, [tex]a=8.68\ m/s^2[/tex]
Explanation:
Given that,
Initial speed of a car, u = 45 km/h = 12.5 m/s
Final speed, v = 0 (as they comes to rest)
Distance, d = 18 m
We need to find the acceleration of the breaking car. Using third equation of motion as follows :
[tex]v^2-u^2=2ad\\\\\text{Where a is acceleration of the car}\\\\a=\dfrac{v^2-u^2}{d}\\\\a=\dfrac{(12.5)^2}{18}\\\\a=8.68\ m/s^2[/tex]
So, the acceleration of the braking car is [tex]8.68\ m/s^2[/tex].
