a plane being propelled due east is actually moving at 225mph an angle of 40 degrees north of east 144.63 mph is the crosswind that’s is blowing due north. if there was no wind and the plane continued propelling itself with the same force and direction as before how fast would it be traveling due east ?

Respuesta :

Answer:

172.36

Explanation:

The Pythagoras' Theorem allows finding the speed of the plane traveling east is:

         R = 172.36 mph

Given parameters

  • The final speed of the plane [tex]v_p[/tex] = 225 mph, θ = 40º North of the east
  • Wind speed [tex]v_w[/tex] = 144.63 mph towards North

Velocity is a vector, so to add it, vector algebra must be used.

One way to solve is to find the modulus with the Pythagoras' Theorem the direction using trigonometry.  

In the attachment we can see a diagram of the velocity vectors, we see that the question corresponds to one of the legs of the triangle.

       

          v_ₐ² = [tex]v_w^2 + r^2[/tex]

          r² = v_ₐ² - [tex]v_W^2[/tex]

          r = [tex]\sqrt{225^2 - 144.63^2}[/tex]

          r = 172.36 mph

In conclusion using the Pythagoras' Theorem we find the velocity of the plane towards the east is:

         r = 172.36 mph

Learn more about Pythagoras'  theorem here:

https://brainly.com/question/343682

Ver imagen moya1316