Respuesta :
Answer:
800 mg/ml
Explanation:
Recall that: 1 g = 1000 mg.
Hence
3.2 g of CaCl2 = 3.2 x 1000 = 3200 mg CaCl2
mass concentration of CaCl2 = mass of CaCl2/volume of water
= 3200/4 (mg/ml)
= 800 mg/ml
Therefore, the concentration (in mg/ml) of CaCl salt solution formed by dissolving 3.2g of CaCl2 in 4 ml of water is 800 mg/ml.
The concentration of calcium chloride solution will be 800 mg/ml.
The calculation of the concentration of CaCl₂:
Based on the given information,
- The mass of CaCl₂ given is 3.2 grams.
- The volume of water is 4 ml.
Now the concentration of CaCl₂ can be determined as,
Concentration = Mass/Volume
Now putting the values we get,
[tex]Conc = \frac{3.2 g}{4 ml} \\Conc = 0.8 g/ml\\Conc = 0.8 g * 1000 mg/ml\\Conc = 800 mg/ml[/tex]
Thus, the concentration of CaCl₂ is 800 mg/ml.
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