merinoesther831
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An astronaut drops a feather from 1.2 m above
the surface of the moon. If the acceleration of
gravity on the moon is 1.62 m/s2 downward,
how long does it take the feather to hit the
moon's surface?

Respuesta :

Cricetus

It take "1.49 sec" to hit the moon's surface. A further explanation is provided below.

According to the question,

Height,

  • d = 1.2 m/s

Acceleration of gravity,

  • a = 1.62 m/s²

Initial velocity,

  • u = 0

With the help of the equation,

→ [tex]t^2 = \frac{2d}{a}[/tex]

By substituting the values, we get

→     [tex]= \frac{2\times 1.2}{1.62}[/tex]

→     [tex]= \frac{2.4}{1.62}[/tex]

→     [tex]= 1.49 \ sec[/tex]

Thus the above answer is right.

Learn more:

https://brainly.com/question/9487196

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