Answer:
A.) 230 km
B.) 76.67 km/h
Explanation:
Given that On a straight road (taken to be in the +x direction) you drive for an hour at 50 km per hour, then quickly speed up to 90 km per hour and drive for an additional two hours.
A.) How far do you go?
When driving for an hour, the distance covered will be
Distance = speed × time
Distance = 50 × 1 = 50 km
When driving for additional 2 hours, the distance covered will be
Distance = 90 × 2 = 180 km
Total distance = 180 + 50 = 230 km
b. What is your average x component of velocity?
Average Velocity = total distance/ total time
Average velocity = 230/3
Average velocity = 76.67 km/h
c. Why isn't vavg,x equal to the arithmetic average of your initial and final values of vx, (50+90)/2 = 70 km per hour
They are not equal because of the displacement is the same as distance travelled.
A) How far do you go
Displacement = Velocity * time
Total displacement, [tex]x = 50 * 1 + 90 * 2[/tex]
x = 230km
B) The average velocity is
average velocity = [tex]\frac{total displacement}{Total time taken}[/tex]
[tex]Ave velocity = \frac{230}{1+2}\\\\ Ave velocity = \frac{230}{3}\\\\ Ave velocity = 76.67km/hr [/tex]
C) Why isn't vavg,x equal to the arithmetic average of your initial and final values
For more information on average velocity, visit
https://brainly.com/question/6504879
