Answer:
250 m
Explanation:
1. First, we have to calculate the acceleration:
[tex]\boxed{\mathsf{v=v_o+a\cdot t}}[/tex]
where:
v = present velocity
vo = initial velocity
a = acceleration
t = time
2. Let us use given information and substitute in the expression above. Hence:
[tex]\mathsf{50=0+a\cdot10}\\\\\mathsf{50=10\cdot a}\\\\\mathsf{a=\dfrac{50}{10}}\\\\\therefore \boxed{\mathsf{a=5\,m/s^2}}}[/tex]
3. Now we can calculate traveled distance with Torricelli's equation:
[tex]\boxed{\mathsf{v^2=v_o^2+2\cdot a \cdot d}}[/tex]
where:
v = present velocity
vo = initial velocity
a = accelerarion
d = distance
4. So, we get:
[tex]\mathsf{50^2=0^2+2\cdot 5 \cdot d}\\\\\mathsf{2500=10\cdot d}\\\\\mathsf{d=\dfrac{2500}{10}}\\\\\therefore \boxed{\mathsf{d=250\,m}}[/tex]
Conclusion: during 10 seconds the truck has traveled a distance of 250 m.
Have a nice day! : )
