Zaracarson06
contestada

Some friends want to see a movie that is showing at two different theaters in town. They plan to share three tubs of popcorn during the movie.

Movie theatre prices. Theatre A: ticket price 14 dollars 50 cents, popcorn 5 dollars 75 cents. Theatre B: ticket price 13 dollars, popcorn 6 dollars 75 cents.

Respuesta :

facundo3141592

Answer:

Let's call x as the number of friends, now, in Theatre A we have:

Price for x tickets = x*$14.50

price for 3 tubs of popcorn = 3*$5.75 = $17.25

Total price:

Pa(x) = $14.50*x + $17.25

Now, for Theatre B we have:

Price for x tickets = $13*x.

Price for 3 tubs of popcorn: = 3*$6.75 = $20.25

Total price:

Pb(x) = $13*x + $20.25.

Now, we can find the number of friends x in such case that they will pay the same in each theater by:

Pa(x) = Pb(x)

$14.50*x + $17.25 = $13*x + $20.25.

Now we solve this for x:

($14.50 - $13)*x = $20.25 - $17.25 = $3

$1.50*x = $3

x = $3/$1.50 = 2.

Then, if there are 2 friends, they will pay the same in both theatres

If there are more tha 2 friends, the cheaper place will be Theatre B, because the slope is smaller, which means that for each additional ticket the total price will increase less.