Answer:
59
Step-by-step explanation:
[tex]5-2\times \:3+6\left(3^2+1\right)\\\\\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}\\\\\mathrm{Calculate\:within\:parentheses}\:\left(3^2+1\right)\::\quad 10\\\\=5-2\times \:3+6\times \:10\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:2\times \:3\::\quad 6\\=5-6+6\times \:10\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:6\times \:10\::\quad 60\\\\=5-6+60\\\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:5-6+60\:\\\\:\quad 59[/tex]
