Respuesta :
Answer:
(a). Their speed during that run is 10 m/s.
(b). Their velocity is 6.86 m/s
(c). The final position is at 8.91 m.
Explanation:
Given that,
A football player starts at the 40-yard line, and runs to the 25-yard line in 2 seconds.
Suppose, the distance between 40 yard line and 25 yard line is 20 yard.
(a). We need to calculate their speed during that run
Using formula of speed
[tex]v=\dfrac{d}{t}[/tex]
Where. d = distance
t = time
Put the value into the formula
[tex]v=\dfrac{18.288}{2}[/tex]
[tex]v=10\ m/s[/tex]during that run
(b). We need to calculate their velocity
Using formula of speed
[tex]v=\dfrac{\Delta d}{\Delta t}[/tex]
Put the value into the formula
[tex]v=\dfrac{22.86-36.58}{2}[/tex]
[tex]v=-6.86\ m/s[/tex]
Negative sign shows the direction of motion.
(c). If they kept running at that velocity for another 1.3 seconds,
We need to calculate the final position
Using formula of position
[tex]d=vt[/tex]
Put the value into the formula
[tex]d=6.86\times1.3[/tex]
[tex]d=8.91\ m[/tex]
Hence, (a). Their speed during that run is 10 m/s.
(b). Their velocity is 6.86 m/s
(c). The final position is at 8.91 m.
