Answer:
The value is [tex]V_n = 2.2498 \ m^3[/tex]
Explanation:
From the question we are told that
The volume of liquid nitrogen is [tex]V_n = 3.6 \ L= 3.6 *10^{-3} \ m^3[/tex]
The density of nitrogen at gaseous form is [tex]\rho_n = 1.2929 \ kg/m^3[/tex] = The dry air at sea level
Generally the density of nitrogen at liquid form is
[tex]\rho _l = 808 \ kg/m^3[/tex]
And this is mathematically represented as
[tex]\rho_l = \frac{m}{V_l }[/tex]
=> [tex]m = \rho_l * V_l[/tex]
Now the density of gaseous nitrogen is
[tex]\rho_n = \frac{m}{V_n }[/tex]
=> [tex]m = \rho_n * V_n[/tex]
Given that the mass is constant
[tex]\rho_n * V_n = \rho_l * V_l[/tex]
[tex]1.2929* V_n = 808 * 3.6*10^{-3}[/tex]
=> [tex]V_n = 2.2498 \ m^3[/tex]
