Answer:
18808.7 m/s^2
Explanation:
Given
Length of the pendulum L = 1.44 m
Number of complete cycles of oscillation n = 1.10 x 10^2
total time of oscillation t = 2.00 x 10^2 s
The period of the T = n/t
T = (1.10 x 10^2)/(2.00 x 10^2) = 0.55 ^-s
The period of a pendulum is gotten as
T = [tex]2\pi \sqrt{\frac{L}{g} }[/tex]
where g is the acceleration due to gravity
substituting values, we have
0.55 = [tex]2\pi \sqrt{\frac{1.44}{g} }[/tex]
0.0875 = [tex]\sqrt{\frac{1.44}{g} }[/tex]
squaring both sides of the equation, we have
7.656 x 10^-3 = 144/g
g = 144/(7.656 x 10^-3) = 18808.7 m/s^2
