Answer:
The probability is [tex]P(X > 25 ) = 1.667[/tex]
Step-by-step explanation:
From the question we are told that
The maximum wait is [tex]b = 30 \ minutes[/tex]
The minimum wait would be [tex]a = 0\ minutes[/tex]
Generally the probability that you will wait more than 25 minutes for a bus is mathematically represented as
[tex]P(X > 25 )[/tex]
Now given that the time a person waits is uniformly distributed and that the maximum is 30 then we can evaluate the above probability as
[tex]P(X > 25 ) = P(25 < X < 30 ) = \frac{30 - 25}{30 - 0}[/tex]
[tex]P(X > 25 ) = 1.667[/tex]
