Answer:
The value is [tex]a = - 4.45 m/s^2[/tex]
Explanation:
From the question we are told that
The initial speed is [tex]u = 28 \ m/s[/tex] at a distance of [tex]s_1 = 0 \ m[/tex]
The final speed is [tex]v = 0 \ m/s[/tex] at a distance of [tex]s_2 = 88 \ m[/tex]
Generally from the kinematic equation we have that
[tex]v^2 = u^2 +2as[/tex]
=> [tex]a = \frac{v^2 - u^2 }{ 2(s_2 - s_1 )}[/tex]
=> [tex]a = \frac{0 - 28^2 }{ 2(88 - 0 )}[/tex]
=> [tex]a = - 4.45 m/s^2[/tex]
The negative sign shows that it is decelerating
