Functions stuff. Picture attached. 30 points. thanks <3

Answer:
A
Step-by-step explanation:
So we have the function:
[tex]f(x)=\frac{3+x}{x-3}[/tex]
And we want to find:
[tex]f(a+2)[/tex]
To do so, substitute in (a+2) for x:
[tex]f(a+2)=\frac{3+(a+2)}{(a+2)-3}[/tex]
Simplify the numerator and denominator. Add 2 and 3 in the numerator. Subtract in the denominator:
[tex]f(a+2)=\frac{5+a}{a-1}[/tex]
The answer is A.
Answer:
[tex]\Large \boxed{\mathrm{A}}[/tex]
Step-by-step explanation:
[tex]\displaystyle f(x) = \frac{3+x}{x-3}[/tex]
For f(a + 2), the input for the function f(x) is (a + 2).
Replacing x with (a + 2).
[tex]\displaystyle f(a+2) = \frac{3+(a+2)}{(a+2)-3}[/tex]
Simplify the rational function.
[tex]\displaystyle f(a+2) = \frac{(3+2)+a}{a+(2-3)}[/tex]
[tex]\displaystyle f(a+2) = \frac{5+a}{a-1}[/tex]