Answer: (x+4)^2-3
This is equivalent to x^2+8x+13
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Explanation:
The vertex of f is at (0,0). The vertex of g is at (-4, -3). The vertex has moved 4 units to the left and 3 units down.
To shift to the left, we replace x with x+4. So we have f(x) = x^2 turn into f(x+4) = (x+4)^2 so far.
Then we subtract off 3 to move everything 3 units down. We have
g(x) = (x+4)^2-3
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Optionally we can expand things out like so
g(x) = (x+4)^2-3
g(x) = (x+4)(x+4)-3
g(x) = x(x+4)+4(x+4)-3
g(x) = x^2+4x+4x+16-3
g(x) = x^2+8x+13
Showing that (x+4)^2-3 is equivalent to x^2+8x+13
