Given: The area of a square field is 841 sq.m
Since side of square = √Area
So, side of square field = [tex]\sqrt{841} =29[/tex]
Thus , side of square field = 29 m
Perimeter of square = 4( side) = 4(29) = 116 m
Let x be the breadth of rectangle then 2x be the length
Perimeter of rectangle = 2 (length+breadth) = 2(2x+x)= 2(3x)=6x
As per question, perimeter of rectangle= Perimeter of square
[tex]\Rightarrow\ 6x=116\\\\\Rightarrow\ x=\dfrac{116}{6}=\dfrac{58}{3}\ m[/tex]
Length : [tex]2x =2\dfrac{58}{3}=\dfrac{116}{3}\ m[/tex]
Area of rectangle = length x breadth
[tex]=\dfrac{116}{3}\times\dfrac{58}{3}=\dfrac{6728}{9}\\\\=747\dfrac{5}{9}\ m^2[/tex]
Area of rectangle = [tex]747\dfrac{5}{9}\ m^2[/tex]
