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Two identical resistors were connected in parallel and their equivalent resistance was
4 ohm. If the two resistors were connected in series, then their equivalent resistance
(in ohm) would be:
Select one:
a. 30
b.4
c. 16
d. 8
O e. 2
Å

Respuesta :

Answer:

C

Explanation:

Rt= total resistance

we know that 1/Rt=1/R1+1/R2(from ohm's law)

Since, Rt=4 and R1=R2

we will get,

1/4=2/R2

R2=8

when in series Rt=R1+R2,

So, Rt=8+8=16 ohm's

Eduard22sly

If the two resistors are connected in series, then their equivalent resistance (in ohm) will be 16 ohms

The correct answer to the question is Option C. 16 ohms

Fact from the question

Since the two resistors are identical, then

R₁ = R₂

Determination of the two resistors

•Equivalent resistance (Rₜ) = 4 Ohms

•Resistor 1 (R₁) = Resistor 2 (R₂) =?

In parallel connection,

Rₜ = (R₁ × R₂) / (R₁ + R₂)

4 = (R₁ × R₁) / (R₁ + R₁)

4 = R₁² / 2R₁

4 = R₁ / 2

Cross multiply

R₁ = 4 × 2

R₁ = 8 Ohms

Thus,

R₂ = R₁ = 8 Ohms

Determination of the equivalent resistance in series

•Resistor 1 (R₁) = 8 Ohms

•Resistor 2 (R₂) = 8 Ohms

•Equivalent resistance (Rₜ) =?

In series connection,

Rₜ = R₁ + R₂

Rₜ = 8 + 8

Rₜ = 16 Ohms

Thus, the correct answer to the question is Option C. 16 ohms

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