Respuesta :

Answer:

C, D, and F

Step-by-step explanation:

The roots of the cubic polynomial are 1, (5+√17)/2, and (5-√17)/2 options (C), (D), and (F) are correct.

What is polynomial?

Polynomial is the combination of variables and constants systematically with "n" number of power in ascending or descending order.

[tex]\rm a_1x+a_2x^2+a_3x^3+a_4x^4..........a_nx^n[/tex]

We have a cubic or third-degree polynomial:

F(x) = x³ - 6x² + 7x - 2

To find the all possible roots of the cubic polynomial

By using the trial and error method:

Plug x = 1

F(1) = 1 - 6 + 7 - 2

F(1) = 8 - 8

F(1) =0

x = 1 is one of the roots of the polynomial.

We can write the cubic polynomial in the factored form:

F(x) = (x - 1)(x² -5x + 2)

We have a quadratic polynomial:

= x² -5x + 2

To find the roots of the quadratic polynomial use the quadratic formula:

a= 1, b = -5, and c =2

[tex]\rm x = \dfrac{-b \pm\sqrt{b^2-4ac}}{2a}[/tex]

[tex]\rm x = \dfrac{-(-5) \pm\sqrt{(-5)^2-4(1)(2)}}{2(1)}[/tex]

After solving:

x = (5+√17)/2

x = (5-√17)/2

Thus, the roots of the cubic polynomial are 1, (5+√17)/2, and (5-√17)/2 options (C), (D), and (F) are correct.

Learn more about Polynomial here:

brainly.com/question/17822016

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